Before You Begin
Question #40302
The Question
Let be the set of all real values of for which the improper integral converges. Which of the following represents the set ?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Specialist
Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.
Concepts Behind This Question
Universal Set Relativity|Even and Odd Function Symmetry|The Modulus Trap|Improper Integrals
Why This Question Is Tricky
Common Mistakes
This question tests the student's understanding of improper integrals and the limitations of definite integral properties (specifically King's Property).
A common trap in JEE Advanced is to blindly apply the identity for an odd function .
While this identity holds for convergent integrals, applying it here artificially increases the degree of the numerator (since ), masking the true singularity at .
Students falling for this 'Modulus/Symmetry Trap' will incorrectly conclude the integral converges for because the Cauchy Principal Value exists.
However, true convergence of an improper integral over requires independent convergence on and , which reveals the correct domain .
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Sets - Class 11 |
| Concept | Universal Set Relativity |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |