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Question #40305

Difficulty: 8/10 | 🟢 Free

The Question

Let A={x∈R:x2−4x+3≤0}A = \{x \in \mathbb{R} : x^2 - 4x + 3 \le 0\} and B={x∈R:x2−6x+8≤0}B = \{x \in \mathbb{R} : x^2 - 6x + 8 \le 0\}. A function g:A∪B→Rg: A \cup B \to \mathbb{R} is defined as: g(x)={x2−5if x∈A∖B2x−5if x∈A∩B2x−7if x∈B∖Ag(x) = \begin{cases} x^2 - 5 & \text{if } x \in A \setminus B \\ 2x - 5 & \text{if } x \in A \cap B \\ 2x - 7 & \text{if } x \in B \setminus A \end{cases} Let f(x)=∫2xg(t) dtf(x) = \int_{2}^{x} g(t) \, dt. If SS is the set of all interior points in the domain of ff where f(x)f(x) attains a local extremum, then the sum of all elements in SS is:

Options

  • A.

    66

  • B.

    88

  • C.

    99

  • D.

    1111

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Venn Diagram Overlap Logic|Non-Differentiable Extrema|Right-Hand vs Left-Hand Derivatives

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to map set-theoretic operations (Venn diagram regions) to piecewise analytical functions and identify non-differentiable extrema.

The primary trap lies at the intersection boundary x=3x=3.

Students commonly rely solely on Fermat's Theorem (f′(x)=0f'(x)=0) to find local extrema, which correctly identifies the differentiable minima at x=2.5x=2.5 and x=3.5x=3.5.

However, they frequently overlook the sharp turn (cusp) at x=3x=3 where the left-hand derivative is positive and the right-hand derivative is negative, creating a non-differentiable local maximum.

Missing this boundary extremum leads directly to the trap option of 6.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterSets - Class 11
ConceptVenn Diagram Overlap Logic
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree