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Question #40335

Difficulty: 8/10 | 🟢 Free

The Question

Let AA be a set containing nn elements, where nn is the number of distinct terms in the expansion of (x+y+z)4(x−y+z)4(x + y + z)^4 (x - y + z)^4. If the total number of reflexive relations on set AA is 2k2^k, then the value of kk is:

Options

  • A.

    600

  • B.

    210

  • C.

    1190

  • D.

    20

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Total Number of Relations|Sigma Notation Properties|Expansion of Products of Binomials

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to correctly determine set cardinality from the expansion of a product of multinomials before applying relation formulas.

The primary trap lies in the misinterpretation of the expansion (x+y+z)4(x−y+z)4(x+y+z)^4(x-y+z)^4.

Students often incorrectly assume it behaves as a standard trinomial (4+3−12)=15\binom{4+3-1}{2}=15 (leading to k=210k=210), or expand it into a 4-term multinomial (x2−y2+z2+2xz)4(x^2-y^2+z^2+2xz)^4 and blindly apply the formula (4+4−13)=35\binom{4+4-1}{3}=35 (leading to k=1190k=1190).

The latter fails because the terms x2,z2,x^2, z^2, and 2xz2xz are not algebraically independent, causing overlaps.

The correct approach requires recognizing the structural identity ((x+z)2−y2)4((x+z)^2-y^2)^4 and summing the distinct terms 9+7+5+3+1=259+7+5+3+1=25 to avoid overlapping term errors, before evaluating the reflexive relation exponent n2−nn^2-n.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterRelations and Functions - Class 11
ConceptTotal Number of Relations
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree