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Question #40345

Difficulty: 8/10 | 🟢 Free

The Question

Let A=(1−1221−14−13)A = \begin{pmatrix} 1 & -1 & 2 \\ 2 & 1 & -1 \\ 4 & -1 & 3 \end{pmatrix} and M(x)=A+xIM(x) = A + x I for x∈Rx \in \mathbb{R}, where II is the 3×33 \times 3 identity matrix. Let P(x)P(x) be a matrix such that M(x)P(x)=IM(x) P(x) = I for all x>0x > 0. Evaluate the limit: lim⁡x→0+1xdet⁡(I−AP(x))\lim_{x \to 0^+} \frac{1}{x} \det(I - A P(x))

Options

  • A.

    15\frac{1}{5}

  • B.

    0

  • C.

    5

  • D.

    \text{Does not exist}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Identity Function Behavior|Inversion and Determinant Product|Singular vs. Non-Singular Threshold|Adjoint-Determinant Relationship

Why This Question Is Tricky

Common Mistakes

This question tests the behavior of the inverse of a matrix as it approaches a singular state (Trap 230).

Students often incorrectly assume that since M(x)P(x)=IM(x)P(x) = I, the limit of P(x)P(x) behaves continuously or acts like A−1A^{-1}, leading them to erroneously conclude that I−AP(x)→0I - AP(x) \to 0 and the determinant is 00.

The trap exposes the failure to recognize that P(x)P(x) is undefined at x=0x=0 (since AA is singular) and requires algebraic manipulation using the identity I−AP(x)=xP(x)I - AP(x) = xP(x) before applying determinant properties.

Furthermore, it tests the precise calculation of the characteristic polynomial coefficients, specifically relying on the trace of the adjoint matrix being exactly zero to yield a finite, non-zero limit.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterRelations and Functions - Class 11
ConceptIdentity Function Behavior
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree