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Question #40348

Difficulty: 8/10 | 🟢 Free

The Question

Let f(x)=cos⁡−1(1−x21+x2)+csc⁡−1(1+x22x)f(x) = \cos^{-1}\left( \frac{1-x^2}{1+x^2} \right) + \csc^{-1}\left( \frac{1+x^2}{2x} \right) for x>0x > 0. Evaluate the integral: I=∫03f(x)[x] dxI = \int_{0}^{\sqrt{3}} f(x) [x] \,dx where [t][t] denotes the greatest integer less than or equal to tt.

Options

  • A.

    4π33−π−2ln⁡2\frac{4\pi\sqrt{3}}{3} - \pi - 2\ln 2

  • B.

    π3\pi\sqrt{3}

  • C.

    π(3−1)\pi(\sqrt{3} - 1)

  • D.

    4π33−4ln⁡2\frac{4\pi\sqrt{3}}{3} - 4\ln 2

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Constant Function Logic|Domain Constraint Intersections|Greatest Integer Function (GIF)

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to correctly evaluate inverse trigonometric functions outside their principal domains, combined with the discontinuous nature of the Greatest Integer Function (GIF).

A common trap is blindly applying the identity sin⁡−1(sin⁡2θ)=2θ\sin^{-1}(\sin 2\theta) = 2\theta without checking the domain of 2θ2\theta.

For x>1x > 1, 2θ>π/22\theta > \pi/2, forcing the identity to π−2θ\pi - 2\theta, which elegantly collapses the entire expression to a constant π\pi.

Furthermore, the GIF term [x][x] annihilates the non-constant portion of the function on (0,1)(0, 1), punishing students who waste time integrating 4tan⁡−1x4\tan^{-1}x or who ignore the GIF entirely.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterRelations and Functions - Class 11
ConceptConstant Function Logic
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree