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Question #40358

Difficulty: 8/10 | 🟢 Free

The Question

Let A=[aij]A = [a_{ij}] be a square matrix of order 235235, where aij=∣i−j∣234cos⁡(i−j)+∣i−j∣235sin⁡(i−j)a_{ij} = |i-j|^{234} \cos(i-j) + |i-j|^{235} \sin(i-j) for all 1≤i,j≤2351 \le i, j \le 235. Let A=P+QA = P + Q, where PP is a symmetric matrix and QQ is a skew-symmetric matrix. What is the value of det⁡(Q2024+Q2025)+Tr(Q2025)\det(Q^{2024} + Q^{2025}) + \text{Tr}(Q^{2025})?

Options

  • A.

    0

  • B.

    1

  • C.

    235

  • D.

    2025

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Modulus Function Symmetry|Symmetric and Skew-Symmetric Decomposition|Determinant Product Rule

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to identify symmetric and skew-symmetric components hidden behind modulus and trigonometric functions.

The core trap lies in the 'Determinant Product Rule'.

Students often attempt to expand or find patterns in the matrix elements, missing the fundamental properties of skew-symmetric matrices.

By asking for det⁡(Q2024+Q2025)\det(Q^{2024} + Q^{2025}), the problem forces the student to factor the expression into det⁡(Q2024)det⁡(I+Q)\det(Q^{2024})\det(I+Q) to utilize the property that det⁡(Q)=0\det(Q)=0 for odd-order skew-symmetric matrices.

Additionally, asking for the trace of an odd power tests the invariant property that odd powers of skew-symmetric matrices remain skew-symmetric, thus having a zero trace.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterRelations and Functions - Class 11
ConceptModulus Function Symmetry
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree