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Question #40359
The Question
Let be a continuous solution to the differential equation for all . If , then the value of is
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Monster
Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.
Concepts Behind This Question
Modulus Function Symmetry|Linear Differential Equation Structure|Integration Constant Trap
Why This Question Is Tricky
Common Mistakes
This question tests the 'Integration Constant Trap' within a piecewise linear differential equation defined by modulus symmetry.
Students often ignore the modulus, leading to a single incorrect integration constant across the entire domain (yielding ).
Alternatively, they may correctly split the domain but incorrectly assume the integration constant is identical for both sub-domains (), yielding .
The core discriminator is recognizing that continuity at the boundary () is the necessary condition to patch the distinct integration constants together.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Relations and Functions - Class 11 |
| Concept | Modulus Function Symmetry |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |