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Question #40372

Difficulty: 8/10 | 🟢 Free

The Question

Let f:D→Rf: D \to \mathbb{R} be a function defined by f(x)=2sgn(x4−6x3+13x2−12x+4x3−4x2+5x−2)+sgn(x2−3x+2)f(x) = 2\text{sgn}\left( \frac{x^4 - 6x^3 + 13x^2 - 12x + 4}{x^3 - 4x^2 + 5x - 2} \right) + \text{sgn}(x^2 - 3x + 2) where DD is the maximal domain of definition of ff in R\mathbb{R}. Which of the following sets represents the range of f(x)f(x)?

Options

  • A.

    {−3,−1,3}\{-3, -1, 3\}

  • B.

    {−3,−2,−1,0,3}\{-3, -2, -1, 0, 3\}

  • C.

    {−3,−1,1,3}\{-3, -1, 1, 3\}

  • D.

    {−3,−2,−1,0,1,2,3}\{-3, -2, -1, 0, 1, 2, 3\}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Domain and Range Nuance|General Equation Transformations|Signum Function Discontinuity

Why This Question Is Tricky

Common Mistakes

This question tests the 'Domain Nuance' and 'Ghost Range' trap associated with the Signum function.

Students often assume sgn(g(x))\text{sgn}(g(x)) will output 00 at the roots of g(x)g(x).

However, if the roots of g(x)g(x) are explicitly excluded from the function's domain (due to the rational function's denominator), the value 00 is never achieved.

Here, simplifying the rational expression yields x−2x-2, tempting students to evaluate the function at the excluded points x=1x=1 and x=2x=2.

Doing so produces the 'ghost' range values −2-2 and 00, leading directly to the primary distractor.

Rigorous domain establishment (D=R∖{1,2}D = \mathbb{R} \setminus \{1, 2\}) is required before applying the signum operator.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterRelations and Functions - Class 11
ConceptDomain and Range Nuance
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree