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Question #40382

Difficulty: 8/10 | 🟢 Free

The Question

Let B=(1101)B = \begin{pmatrix} 1 & 1 \\ 0 & 1 \end{pmatrix}. Let SS be the set of all real numbers xx for which there exists an invertible matrix AA of order 2 with real entries such that AB−B2A=([x]2−5[x]+6)IA B - B^2 A = ([x]^2 - 5[x] + 6)I, where II is the identity matrix of order 2 and [⋅][ \cdot ] denotes the greatest integer function. Find the set SS.

Options

  • A.

    [2, 4)

  • B.

    \emptyset

  • C.

    [2, 3)

  • D.

    (−∞,2)∪[4,∞)(-\infty, 2) \cup [4, \infty)

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

The Empty Set Trap|Inverse Existence Criterion|Greatest Integer Function (GIF)|Matrix Multiplication Non-Commutativity

Why This Question Is Tricky

Common Mistakes

The problem tests the student's understanding of matrix non-commutativity and the existence of inverses.

A common trap is assuming AB=BAAB = BA.

If a student makes this assumption, the equation simplifies to (I−B)BA=kI(I-B)BA = kI.

Taking determinants gives det⁡(I−B)det⁡(B)det⁡(A)=k2\det(I-B)\det(B)\det(A) = k^2.

Since det⁡(I−B)=0\det(I-B) = 0, this forces k=0k = 0, leading to (I−B)A=0(I-B)A = 0, which implies det⁡(A)=0\det(A) = 0.

This contradicts the requirement that AA is invertible, leading the student to incorrectly conclude that no such xx exists (the 'Empty Set' trap).

By correctly treating AA and BB as non-commutative, a valid family of invertible matrices is found, yielding a non-empty solution set for xx.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterSets - Class 11
ConceptThe Empty Set Trap
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree