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Question #40396

Difficulty: 8/10 | 🟢 Free

The Question

Let ak=(3k)cos⁡(kπ2)a_k = \binom{3}{k} \cos\left(\frac{k\pi}{2}\right) and bk=(3k)sin⁡(kπ2)b_k = \binom{3}{k} \sin\left(\frac{k\pi}{2}\right) for k=0,1,2,3k=0,1,2,3. A continuous curve CC in the first quadrant (x>0,y>0x > 0, y > 0) satisfies the differential equation: xdydx−y=x∑k=03bkx3−kyk∑k=03akx3−kykx \frac{dy}{dx} - y = x \frac{\sum_{k=0}^{3} b_k x^{3-k} y^k}{\sum_{k=0}^{3} a_k x^{3-k} y^k} If CC passes through the point (1,1)(1, 1), which of the following is a possible value of the slope of the ray from the origin to a point on CC?

Options

  • A.

    74\frac{7}{4}

  • B.

    95\frac{9}{5}

  • C.

    32\frac{3}{2}

  • D.

    2

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Allied Angle Periodicity|General Term Formulation|Substitution Logic in Homogeneous DE

Why This Question Is Tricky

Common Mistakes

This question tests the intersection of complex binomial expansions and the topological domain of homogeneous differential equations.

The primary trap lies in the substitution v=y/xv = y/x.

Students typically integrate the separated variables to find the algebraic curve 16x3=v(3−v2)416x^3 = v(3-v^2)^4 and incorrectly assume vv can take any positive value since the equation yields a real xx.

However, the periodic nature of the allied angle coefficients masks the fact that QP=tan⁡(3arctan⁡v)\frac{Q}{P} = \tan(3 \arctan v), which introduces a singularity at v=3v = \sqrt{3} where x→0x \to 0.

Because the curve is restricted to the first quadrant (x>0x > 0), it cannot cross this singular boundary.

Failing to explicitly constrain the periodicity of the solution branch leads students to erroneously accept values like 7/47/4 or 22, missing that the valid domain for this specific branch is strictly v∈(0,3)v \in (0, \sqrt{3}).

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterTrigonometric Functions - Class 11
ConceptAllied Angle Periodicity
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree