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Question #40483

Difficulty: 8/10 | 🟢 Free

The Question

Let S={z∈C:z8=1}S = \{z \in \mathbb{C} : z^8 = 1\}. A multiset MM is formed by applying the transformation f(z)=zsgn(Im(z))f(z) = z^{\text{sgn}(\text{Im}(z))} to each z∈Sz \in S, where sgn(x)\text{sgn}(x) denotes the signum function. Find the number of distinct linear arrangements of all elements of MM such that no two identical elements are adjacent.

Options

  • A.

    864

  • B.

    2220

  • C.

    1656

  • D.

    2520

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Roots of Unity Properties|String Method (Adjacency)|Signum Function Discontinuity

Why This Question Is Tricky

Common Mistakes

This question tests the intersection of complex number properties and advanced combinatorics (Inclusion-Exclusion Principle).

The primary trap lies in the discontinuity of the signum function at zero.

Students often incorrectly assume sgn(Im(z))\text{sgn}(\text{Im}(z)) evaluates to 11 or −1-1 for all roots, forgetting that the real roots 11 and −1-1 have an imaginary part of exactly 00.

This oversight leads to f(−1)=−1f(-1) = -1, resulting in a multiset with only 3 pairs instead of 4, yielding the trap answer 2220.

Recognizing that z0=1z^0 = 1 for both real roots correctly establishes the 4-pair multiset structure required for the String Method.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterComplex Numbers and Quadratic Equations - Class 11
ConceptRoots of Unity Properties
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree