Before You Begin
Question #40523
The Question
Let be the set of all integers that satisfy the inequality: Find the number of elements in .
Options
- A.
8
- B.
9
- C.
10
- D.
7
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Specialist
Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.
Concepts Behind This Question
Even Multiplicity Roots|Modulus Inequality Logic|Limit Existence at Discontinuity
Why This Question Is Tricky
Common Mistakes
This question tests the 'Limit Existence at Discontinuity' trap within a modulus inequality.
Students commonly apply the wavy-curve method or sign-chart logic directly to the expression, noting that the denominator makes the function undefined at .
Consequently, they incorrectly exclude from the solution set, yielding 8 integers.
However, the inequality is defined via a limit.
Because the zero at has an even multiplicity in both the numerator (via the cosine expansion) and the denominator, the limit exists, is negative, and satisfies the inequality, making a valid solution.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Linear Inequalities - Class 11 |
| Concept | Even Multiplicity Roots |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |