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Question #40529

Difficulty: 8/10 | 🟢 Free

The Question

Let f(x)=∣x2−34x+271∣x2−34x+245f(x) = \frac{|x^2 - 34x + 271|}{x^2 - 34x + 245}. Let S1S_1 be the sum of all xx where f(x)f(x) attains a local maximum, and S2S_2 be the sum of all xx where f(x)f(x) attains a local minimum. If f(x)f(x) is non-differentiable at exactly kk points in its domain, find the value of S1−S2+kS_1 - S_2 + k.

Options

  • A.

    17

  • B.

    19

  • C.

    21

  • D.

    36

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Denominator Restriction|Completing the Square in Quadratics|Modulus Function Breakdown|Non-Differentiable Extrema

Why This Question Is Tricky

Common Mistakes

This question tests the 'Modulus Breakdown' and 'Denominator Restriction' traps.

Students often mechanically differentiate to find extrema, incorrectly assuming f′(x)=0f'(x) = 0 is a necessary condition, thereby missing the non-differentiable local maxima (cusps) at the roots of the modulus argument.

Furthermore, the denominator restriction creates vertical asymptotes; a common trap is counting these asymptotes as points of non-differentiability, failing to realize they are excluded from the function's domain.

The constants 245 and 271 are specifically chosen to force a domain analysis where the modulus roots lie strictly between the local minimum and the asymptotes.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterLinear Inequalities - Class 11
ConceptDenominator Restriction
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree