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Question #40569

Difficulty: 8/10 | 🟢 Free

The Question

Five married couples are to be seated around a circular table with 1010 identical chairs. In how many ways can they be seated such that men and women alternate, and no husband sits next to his own wife?

Options

  • A.

    312

  • B.

    384

  • C.

    1056

  • D.

    1560

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Circular Permutations Constraint|Derangements (Inclusion-Exclusion)|Complementary Counting

Why This Question Is Tricky

Common Mistakes

This question tests the classic Menage problem, combining the Gap Method for circular permutations with Inclusion-Exclusion for derangements.

The primary trap is complementary counting without accounting for the circular nature of the forbidden adjacencies, often leading students to use the incorrect linear coefficient (10−kk)\binom{10-k}{k} (yielding 384).

The secondary trap tests circular symmetry: students often forget to fix one person to break the rotational invariance, incorrectly using 5!5! for the men and arriving at 1560.

Another common error is assuming standard derangements (D5=44D_5=44), ignoring that each person has two forbidden adjacent seats, leading to 1056.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterPermutations and Combinations - Class 11
ConceptCircular Permutations Constraint
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree