Start Learning Free

Before You Begin

Question #40631

Difficulty: 8/10 | 🟢 Free

The Question

Let SnS_n be the set of all polynomials Q(x)Q(x) of degree nn with real coefficients such that the coefficient of xnx^n is 11. Let mn=min⁡Q∈Sn∫01(Q(x))2dxm_n = \min_{Q \in S_n} \int_{0}^{1} (Q(x))^2 dx. Find the value of lim⁡n→∞n⋅mn⋅(2nn)2\lim_{n \to \infty} n \cdot m_n \cdot \binom{2n}{n}^2.

Options

  • A.

    14\frac{1}{4}

  • B.

    12\frac{1}{2}

  • C.

    1

  • D.

    2

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Coefficient of x^r in Expansion|Symmetry Utilization|Inequalities in Definite Integrals

Why This Question Is Tricky

Common Mistakes

This question tests the intersection of orthogonal polynomials, integral inequalities, and exact coefficient extraction.

The trap lies in attempting to bound the integral using standard inequalities (like Cauchy-Schwarz on the polynomial coefficients), which yields a loose lower bound that fails to evaluate the limit.

The 'Lethal Collision' occurs because students must realize that the minimum norm is achieved by the orthogonal projection (shifted Legendre polynomial), requiring them to extract its exact leading coefficient via Rodrigues' formula and evaluate the integral using repeated integration by parts to find the exact limit.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterBinomial Theorem - Class 11
ConceptCoefficient of x^r in Expansion
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree