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Question #40640
The Question
Let be the number of ways to distribute 20 identical items among 3 distinct boxes such that exactly one box is empty. Consider the binomial expansion of in increasing powers of . If , let be the index of the algebraically greatest term in the expansion. Find the value of .
Options
- A.
25
- B.
26
- C.
27
- D.
29
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Specialist
Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.
Concepts Behind This Question
Numerically Greatest Term|Distributing Identical Items (Stars and Bars)|Constant Function Logic|Sign Flipping Rule
Why This Question Is Tricky
Common Mistakes
This question tests the critical distinction between the Numerically Greatest Term (NGT) and the algebraically greatest term in a binomial expansion with a negative parameter.
Students typically calculate the NGT index using the standard formula , which yields , pointing to .
The primary trap is failing to apply the 'Sign Flipping Rule': because the term is negative, is actually the algebraically least term.
A secondary trap occurs when students realize the term must be positive (odd index) and mistakenly choose because its index is numerically closer to than .
However, due to the skewed binomial distribution, is strictly greater than , forcing students to analytically compare the adjacent positive terms rather than relying on proximity.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Binomial Theorem - Class 11 |
| Concept | Numerically Greatest Term |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |