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Question #40654

Difficulty: 8/10 | 🟢 Free

The Question

Consider the function f(x)=(1+x2)−3f(x) = \left(1 + \frac{x}{2}\right)^{-3} and its quadratic Maclaurin polynomial P(x)=∑k=02(−3k)(x2)kP(x) = \sum_{k=0}^{2} \binom{-3}{k} \left(\frac{x}{2}\right)^k. Let S1S_1 be the set of all integer solutions to the inequality P(x)−1+32xx2−2x−15≤0\frac{P(x) - 1 + \frac{3}{2}x}{x^2 - 2x - 15} \le 0 Let DD be the interval of convergence of the infinite binomial series expansion of f(x)f(x). If S2=S1∩DS_2 = S_1 \cap D, find the number of elements in the set S1∖S2S_1 \setminus S_2.

Options

  • A.

    2

  • B.

    4

  • C.

    5

  • D.

    7

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Properties of Binomial Coefficients|Approximation via Differentials|Wavy Curve (Method of Intervals)

Why This Question Is Tricky

Common Mistakes

This question creates a 'Lethal Collision' between the Wavy Curve method and the domain of validity for binomial approximations.

Students routinely reduce the approximation to a polynomial and solve the algebraic inequality, finding S1S_1.

The primary trap lies in the interval of convergence DD.

Many students either ignore DD entirely (yielding 7 elements) or incorrectly assume the boundary points are included in the domain of convergence (i.e., D=[−2,2]D = [-2, 2]).

If they make the latter mistake, they will incorrectly place −2-2 and 22 into S2S_2, leading to the trap answer of 2.

Furthermore, the wavy curve features a repeated root at x=0x=0, testing if students correctly maintain the sign across the even power.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterBinomial Theorem - Class 11
ConceptProperties of Binomial Coefficients
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree