Before You Begin
Question #40657
The Question
Let be the set of all integers such that the definite integral evaluates to a real number equal to zero. Find the sum of all elements in .
Options
- A.
-779
- B.
-1220
- C.
-820
- D.
-441
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Bridge
Practice problems that bridge the gap between foundational theory and advanced practical application.
Concepts Behind This Question
Expansion of Products of Binomials|V-N Method (Partial Fractions)|Definite Integral Properties (King's Property)|Extraneous Solution Rejection
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to combine algebraic decomposition (V-N method/partial fractions) with definite integral properties, while strictly enforcing domain constraints.
The primary trap lies in blindly applying King's Property () to conclude the integral is always zero, leading students to sum all integers in the given range .
However, the natural logarithm requires its argument to be strictly positive, restricting the valid domain of integration to .
Furthermore, the integral diverges at the boundaries, meaning the limits must strictly reside within this interval.
Students must reject extraneous solutions outside this domain to find the correct sum.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Binomial Theorem - Class 11 |
| Concept | Expansion of Products of Binomials |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |