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Question #40665

Difficulty: 8/10 | 🟢 Free

The Question

Let z1,z2∈Cz_1, z_2 \in \mathbb{C} be non-zero complex numbers such that ∣z1∣2+∣z2∣2=32|z_1|^2 + |z_2|^2 = 32 and arg⁡(z1)=arg⁡(z2)\arg(z_1) = \arg(z_2). Let w1=z1eiαw_1 = z_1 e^{i\alpha} and w2=z2eiβw_2 = z_2 e^{i\beta}, where α∈[π4,π2]\alpha \in \left[\frac{\pi}{4}, \frac{\pi}{2}\right] and β∈[5π6,7π6]\beta \in \left[\frac{5\pi}{6}, \frac{7\pi}{6}\right]. What is the maximum possible value of ∣w1+w2∣|w_1 + w_2|?

Options

  • A.

    434\sqrt{3}

  • B.

    88

  • C.

    454\sqrt{5}

  • D.

    626\sqrt{2}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Arithmetic Mean Inequality|Euler's Form and Rotations|The Modulus Trap

Why This Question Is Tricky

Common Mistakes

The question tests the intersection of algebraic inequalities (AM-GM) and geometric properties of complex numbers (Euler's form and rotations).

The primary trap is the 'Modulus Trap,' where students blindly apply the triangle inequality ∣w1+w2∣≤∣w1∣+∣w2∣|w_1 + w_2| \le |w_1| + |w_2| to conclude the maximum is ∣z1∣+∣z2∣≤8|z_1| + |z_2| \le 8.

This assumes the equality condition arg⁡(w1)=arg⁡(w2)\arg(w_1) = \arg(w_2) is achievable.

However, the domain constraints on the rotation angles α\alpha and β\beta strictly prevent collinearity, forcing the student to evaluate the exact phase difference and maximize the cosine term alongside the AM-GM bound.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterSequences and Series - Class 11
ConceptArithmetic Mean Inequality
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree