Start Learning Free

Before You Begin

Question #40672

Difficulty: 8/10 | 🟢 Free

The Question

For each integer n≥1n \ge 1, let Fn(x)=∫0xex−t(tn−tn+1)dtF_n(x) = \int_0^x e^{x-t} (t^n - t^{n+1}) dt. Define the function H(x)=∑n=1∞Fn(x)H(x) = \sum_{n=1}^{\infty} F_n(x) for x∈[0,1]x \in [0, 1]. Let AA be the left-hand derivative of H(x)H(x) at x=1x=1, and B=∑n=1∞Fn′(1)B = \sum_{n=1}^{\infty} F_n'(1). Find the value of A−BA - B.

Options

  • A.

    0

  • B.

    1

  • C.

    e-1

  • D.

    e-2

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

The Telescopic Series Trap|Leibniz Rule for Differentiation under Integral|Mean Value Theorem Applicability

Why This Question Is Tricky

Common Mistakes

This question tests the danger of blindly interchanging differentiation and infinite summation (a common trap when applying the Mean Value Theorem or Taylor expansions near boundaries).

Students often incorrectly assume that H′(x)=∑Fn′(x)H'(x) = \sum F_n'(x) holds uniformly on the closed interval [0,1][0, 1].

However, because the telescopic sum ∑(xn−xn+1)\sum (x^n - x^{n+1}) converges non-uniformly at x=1x=1, the derivative of the sum (AA) and the sum of the derivatives (BB) diverge exactly at the boundary.

The Leibniz rule correctly identifies the extra boundary terms, exposing the point of non-differentiability of the sum of derivatives.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterSequences and Series - Class 11
ConceptThe Telescopic Series Trap
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree