Before You Begin
Question #40704
The Question
Let . Consider the function defined for all . Find the minimum value of subject to the condition .
Options
- A.
12
- B.
16
- C.
20
- D.
24
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Specialist
Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.
Concepts Behind This Question
Sum of Powers of Natural Numbers|Arithmetic Mean Inequality|Modulus Inequality Logic
Why This Question Is Tricky
Common Mistakes
This question tests the synthesis of optimization via the AM-GM inequality with discrete domain restrictions.
The primary trap lies in the unconstrained optimization: applying AM-GM directly yields a minimum value of 12 at n=3.
Students who blindly apply the inequality without verifying the secondary modulus constraint will select the trap option (A).
The modulus inequality subtly restricts the domain to n ≥ 7, invalidating the AM-GM equality condition.
This forces a piecewise analysis where the student must recognize that the function is strictly increasing for n ≥ 3, making the boundary value n=7 the true constrained minimum.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Sequences and Series - Class 11 |
| Concept | Sum of Powers of Natural Numbers |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |