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Question #40707
The Question
Let . Let be the solution to the initial value problem defined on its maximal interval of existence. Find the number of solutions to the equation .
Options
- A.
0
- B.
1
- C.
2
- D.
3
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Bridge
Practice problems that bridge the gap between foundational theory and advanced practical application.
Concepts Behind This Question
V-N Method (Partial Fractions)|Bernoulli Equation Transformation|Implicit Differentiation Implicit Domain
Why This Question Is Tricky
Common Mistakes
This question tests the intersection of the Method of Differences (V-N method), Bernoulli differential equations, and implicit domain constraints.
The trap is set by the series , which is undefined at because its first term involves division by zero.
Students who blindly apply the telescoping sum will find the algebraic solution and solve to find two roots ( and ).
However, the fundamental theorem of ODEs dictates that the solution to an initial value problem is only valid on the maximal connected interval containing the initial condition where the differential equation is defined.
Since is a singularity, the maximal interval of existence is .
Thus, the second root is extraneous, and ignoring this 'Implicit Domain' leads to an incorrect count of solutions.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Sequences and Series - Class 11 |
| Concept | V-N Method (Partial Fractions) |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |