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Question #40729
The Question
Let be the solution to the differential equation satisfying the initial condition . The minimum value of for is:
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Bridge
Practice problems that bridge the gap between foundational theory and advanced practical application.
Concepts Behind This Question
Slope Sensitivity|Linear Differential Equation Structure|The Modulus Trap
Why This Question Is Tricky
Common Mistakes
The question tests the 'Modulus Trap' within a Linear Differential Equation.
Students must recognize that the modulus forces a piece-wise solution.
The critical trap lies in the 'Slope Sensitivity' and continuity: candidates often incorrectly apply the initial condition directly to the branch, bypassing the continuity requirement at .
This leads to an incorrect constant of integration ( instead of ) and a false minimum of .
Proper execution requires solving the branch first, using the limit at to find the continuity constant for the branch, and then optimizing the resulting curve.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Straight Lines - Class 11 |
| Concept | Slope Sensitivity |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |