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Question #40757

Difficulty: 8/10 | 🟢 Free

The Question

Let EE be the ellipse x225+y216=1\frac{x^2}{25} + \frac{y^2}{16} = 1 and S(3,0)S(3,0) be its focus. A variable point PP lies on EE. The point QQ divides the line segment SPSP internally in the ratio 2:12:1 (i.e., SQ:QP=2:1SQ:QP = 2:1). Let CC be the locus of QQ. If a line LL passing through the origin is tangent to CC, then the square of the slope of LL is:

Options

  • A.

    6491\frac{64}{91}

  • B.

    1611\frac{16}{11}

  • C.

    64109\frac{64}{109}

  • D.

    \text{No such real line exists}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Internal vs External Division|General Conic Definition|Condition of Tangency

Why This Question Is Tricky

Common Mistakes

This question tests the student's geometric intuition versus mechanical calculation.

The primary trap is blindly applying the condition of tangency (c2=a2m2+b2c^2 = a^2m^2 + b^2) to find the slope of a tangent from a given point to a conic, without first verifying if the point lies outside the locus.

Here, the origin lies strictly inside the locus CC, making real tangents impossible.

Mechanical application yields a negative value for m2m^2 (−64/91-64/91), which students often erroneously 'correct' to 64/9164/91 by dropping the negative sign.

Additionally, a secondary trap exists: if a student incorrectly applies the section formula ratio as 1:21:2, the origin falls outside that incorrect locus, yielding a real but incorrect slope squared of 16/1116/11.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterStraight Lines - Class 11
ConceptInternal vs External Division
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree