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Question #40794

Difficulty: 8/10 | 🟢 Free

The Question

Let PP be the parabola x2−2x+4y−11=0x^2 - 2x + 4y - 11 = 0 and ABAB be its chord of contact drawn from the point M(4,1)M(4, 1). Let SS be the region bounded by the parabola PP and the chord ABAB. Evaluate the integral E=540∬S[x2]dy dxE = 540 \iint_S \left[ \frac{x}{2} \right] dy \, dx where [⋅][ \cdot ] denotes the greatest integer function.

Options

  • A.

    270

  • B.

    180

  • C.

    360

  • D.

    25

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Parabola Shifted Vertex|Chord of Contact Logic|Greatest Integer Function (GIF)|Concavity Analysis

Why This Question Is Tricky

Common Mistakes

This question tests the generalized application of the chord of contact (T=0T=0) for a shifted parabola, penalizing students who incorrectly apply origin-vertex formulas.

The core trap lies in the double integral over the bounded region SS with a Greatest Integer Function (GIF) integrand.

Students must correctly analyze the concavity of the parabola to establish the upper and lower bounds (yuppery_{upper} vs ylowery_{lower}) to avoid negative area artifacts.

The GIF forces a split-case integration at x=4x=4, acting as a step-function boundary.

Failing to split the integral or ignoring the 1/41/4 scaling factor from the parabola's equation leads directly to the secondary trap options (180 or 360).

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterConic Sections - Class 11
ConceptParabola Shifted Vertex
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree