Before You Begin
Question #40796
The Question
Let be the set of all continuous functions satisfying for all . The minimum possible value of the definite integral is:
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Bridge
Practice problems that bridge the gap between foundational theory and advanced practical application.
Concepts Behind This Question
Parabola Shifted Vertex|Substitution (Change of Variable)|Compound Function Boundaries|Inequalities in Definite Integrals
Why This Question Is Tricky
Common Mistakes
This question tests the evaluation of definite integrals involving absolute values and compound parabolic boundaries, a common setup for integral inequalities.
The trap lies in the substitution , which shifts the coordinate system.
Students frequently fail to identify the internal roots of the resulting polynomial within the integration interval .
By ignoring the sign change at , they incorrectly compute the net area (yielding ) instead of the absolute area required by the inequality bound, missing the correct answer of .
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Conic Sections - Class 11 |
| Concept | Parabola Shifted Vertex |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |