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Question #40822

Difficulty: 8/10 | 🟢 Free

The Question

Let CtC_t be a family of conics given by the equation x2f(t)+y2g(t)=1\frac{x^2}{f(t)} + \frac{y^2}{g(t)} = 1, where t∈(0,1)t \in (0, 1), f(t)=2+t[3t]+t2sin⁡(1t)f(t) = 2 + t \left[ \frac{3}{t} \right] + t^2 \sin\left(\frac{1}{t}\right), and g(t)=8−t{3t}+4t2sin⁡(1t)g(t) = 8 - t \left\{ \frac{3}{t} \right\} + 4t^2 \sin\left(\frac{1}{t}\right). Here [⋅][ \cdot ] and {⋅}\{ \cdot \} denote the greatest integer and fractional part functions respectively. Let DtD_t be the diameter of CtC_t bisecting a system of parallel chords of slope m=1tm = \frac{1}{t}. If M(t)M(t) is the slope of DtD_t, find the value of lim⁡t→0+M(t)+2tt\lim_{t \to 0^+} \frac{M(t) + 2t}{t}.

Options

  • A.

    25\frac{2}{5}

  • B.

    -2

  • C.

    1

  • D.

    185\frac{18}{5}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Diameter of Conics|Squeeze Theorem (Sandwich Theorem)|Integral Part and Fractional Part

Why This Question Is Tricky

Common Mistakes

This question tests the intersection of coordinate geometry (diameters of conics) and real analysis (limits involving jump discontinuities).

The primary trap lies in evaluating the limit of t[3/t]t [3/t] as t→0+t \to 0^+.

Students frequently make the error of assuming lim⁡t→0t[3/t]=0\lim_{t \to 0} t [3/t] = 0 by treating the GIF as a bounded quantity or incorrectly applying 0×∞0 \times \infty logic.

By forcing the conversion to the fractional part and rigorously applying the Squeeze Theorem, the problem ensures that only students who understand the piecewise bounding of discontinuous parameters will arrive at the correct conic parameters in the singular state.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterConic Sections - Class 11
ConceptDiameter of Conics
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree