Start Learning Free

Before You Begin

Question #40878

Difficulty: 8/10 | 🟢 Free

The Question

Let OO be the origin. The coordinates of three points A,B,A, B, and CC are determined by the roots of the following equations: For AA: t3−7t+6=0t^3 - 7t + 6 = 0 For BB: t3+2t2−5t−6=0t^3 + 2t^2 - 5t - 6 = 0 For CC: t3+3t2−4t−12=0t^3 + 3t^2 - 4t - 12 = 0 The coordinates (x,y,z)(x, y, z) of each point are a permutation of the roots of their respective equations, satisfying the following conditions: (i) AA lies in Octant II, and its yy-coordinate is strictly less than its zz-coordinate. (ii) BB lies in Octant VIII, and its yy-coordinate is strictly greater than its zz-coordinate. (iii) CC lies in Octant VI, and the absolute value of its xx-coordinate is strictly greater than the absolute value of its zz-coordinate. Let VV be the volume of the parallelepiped with coterminous edges OA⃗,OB⃗,\vec{OA}, \vec{OB}, and OC⃗\vec{OC}. If S=[OA⃗ OB⃗ OC⃗]S = [\vec{OA}\ \vec{OB}\ \vec{OC}] is their scalar triple product, find the value of 2V−S2V - S.

Options

  • A.

    99

  • B.

    1818

  • C.

    2727

  • D.

    3636

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Octant Sign Convention|Scalar Triple Product Volume Logic|Vector Product Anti-Commutativity

Why This Question Is Tricky

Common Mistakes

This question tests the student's rigorous understanding of the 3D Cartesian coordinate system's octant sign conventions and the algebraic properties of the Scalar Triple Product (STP).

The primary trap lies in the anti-commutativity of the cross-product embedded within the STP.

Students frequently equate the STP directly to the volume of a parallelepiped, forgetting that the STP yields a signed scalar dependent on the right-handed orientation of the vectors.

By forcing the vectors into specific octants, the determinant naturally evaluates to a negative value (S=−9S = -9).

A student who blindly assumes S=VS = V or drops the negative sign without mathematical justification will incorrectly calculate 2V−S=92V - S = 9 instead of the correct 2727.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterIntroduction to Three-dimensional Geometry - Class 11
ConceptOctant Sign Convention
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree