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Question #40976

Difficulty: 8/10 | 🟢 Free

The Question

Let a line LL be parallel to the vector v⃗=(cos⁡α−sin⁡α)i^+(cos⁡α+sin⁡α)j^+6k^\vec{v} = (\cos \alpha - \sin \alpha)\hat{i} + (\cos \alpha + \sin \alpha)\hat{j} + \sqrt{6}\hat{k}, where α∈[0,2π)\alpha \in [0, 2\pi). Let θ\theta be the angle between the line LL and the plane P:x+y+6z=2024P: x + y + \sqrt{6}z = 2024. If RR and CRC_R denote the range and the coefficient of range of θ\theta respectively, find the ordered pair (R,CR)(R, C_R).

Options

  • A.

    (π3,12)\left( \frac{\pi}{3}, \frac{1}{2} \right)

  • B.

    (π3,1)\left( \frac{\pi}{3}, 1 \right)

  • C.

    (π2,12)\left( \frac{\pi}{2}, \frac{1}{2} \right)

  • D.

    (π6,13)\left( \frac{\pi}{6}, \frac{1}{3} \right)

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Range and Coefficient of Range|Angle between line and plane|Parametric form pitfalls

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to correctly identify the angle between a line and a plane using parametric direction ratios.

The primary trap lies in the formula for the angle: students frequently confuse the angle between the line and the plane (sin⁡θ\sin \theta) with the angle between the line and the normal vector (cos⁡θ\cos \theta).

If a student incorrectly uses cos⁡θ=v⃗⋅n⃗∣v⃗∣∣n⃗∣\cos \theta = \frac{\vec{v} \cdot \vec{n}}{|\vec{v}||\vec{n}|}, they will obtain cos⁡θ∈[1/2,1]\cos \theta \in [1/2, 1], which implies θ∈[0,π/3]\theta \in [0, \pi/3].

While this yields the exact same Range (R=π/3R = \pi/3), it results in an incorrect Coefficient of Range (CR=1C_R = 1), leading them directly to the trap option.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterStatistics - Class 11
ConceptRange and Coefficient of Range
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree