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Question #40983

Difficulty: 8/10 | 🟢 Free

The Question

Let a1,a2,a3a_1, a_2, a_3 be the roots of the equation x3−3x2+4x−5=0x^3 - 3x^2 + 4x - 5 = 0. Let BB be a 3×33 \times 3 matrix defined as: B=(a2+a120a2+a320a1+a22a1+a32a3+a12a3+a220)B = \begin{pmatrix} \frac{a_2+a_1}{2} & 0 & \frac{a_2+a_3}{2} \\ 0 & \frac{a_1+a_2}{2} & \frac{a_1+a_3}{2} \\ \frac{a_3+a_1}{2} & \frac{a_3+a_2}{2} & 0 \end{pmatrix} Find the value of ∣B⋅adj(−2B)∣|B \cdot \text{adj}(-2B)|.

Options

  • A.

    -343

  • B.

    343

  • C.

    -2744

  • D.

    2744

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Properties of Arithmetic Mean|Adjoint-Determinant Relation|Row/Column Exchange Parity

Why This Question Is Tricky

Common Mistakes

This problem tests the interaction between the multilinearity of determinants and row exchange parity.

Students often overlook that matrix BB is a row-swapped version of the standard symmetric arithmetic mean matrix MM, missing the crucial negative sign (∣B∣=−∣M∣|B| = -|M|).

Furthermore, they frequently mishandle the scalar multiplication in the adjoint relation, incorrectly evaluating adj(−2B)\text{adj}(-2B) as −2adj(B)-2\text{adj}(B) or −8adj(B)-8\text{adj}(B), or failing to cube the scalar when taking the determinant of 4∣B∣I34|B|I_3, leading to sign errors or incorrect magnitudes.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterStatistics - Class 11
ConceptProperties of Arithmetic Mean
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree