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Question #41012

Difficulty: 8/10 | 🟢 Free

The Question

A biased coin with probability of showing heads p∈(0,1)p \in (0, 1) is tossed 66 times independently. Let AA be the event that the first toss shows heads, and SS be the event that the total number of heads obtained in the 66 tosses is either 22 or 33. If AA and SS are independent events, then the value of pp is:

Options

  • A.

    2−1\sqrt{2} - 1

  • B.

    5−12\frac{\sqrt{5} - 1}{2}

  • C.

    3−12\frac{\sqrt{3} - 1}{2}

  • D.

    3−2\sqrt{3} - \sqrt{2}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Mutually Exclusive vs Independent|Bernoulli Trials Logic|General Term Formulation

Why This Question Is Tricky

Common Mistakes

This question targets the conceptual collision between independent trials and mutually exclusive sub-events within a binomial framework.

The trap lies in assuming that the independence of individual coin tosses automatically simplifies the intersection of macroscopic events, or incorrectly applying the addition rule P(A∪B)P(A \cup B) instead of rigorously evaluating the intersection P(A∩S)P(A \cap S).

Students often fail to correctly partition the sample space for A∩SA \cap S, forgetting that fixing the first trial restricts the binomial general term to the remaining n−1n-1 trials.

By forcing the algebraic expansion of the independence condition P(A∩S)=P(A)P(S)P(A \cap S) = P(A)P(S), the problem tests whether the student can accurately navigate localized sample space reductions without violating the fundamental definitions of probability.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterProbability - Class 11
ConceptMutually Exclusive vs Independent
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree