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Question #41119

Difficulty: 8/10 | 🟢 Free

The Question

The number of real roots of the equation tan⁡−1(2x1−x2)+tan⁡−1(3x−x31−3x2)=π4\tan^{-1}\left(\frac{2x}{1-x^2}\right) + \tan^{-1}\left(\frac{3x-x^3}{1-3x^2}\right) = \frac{\pi}{4} is

Options

  • A.

    1

  • B.

    2

  • C.

    3

  • D.

    4

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Injective Mapping (One-One)|Composite Injectivity/Surjectivity|Principal Value Branch Boundaries|The Sum-Difference Formula Constraints

Why This Question Is Tricky

Common Mistakes

This question tests the understanding of principal value branch boundaries in composite inverse trigonometric functions.

A common trap is blindly applying the identities tan⁡−1(2x1−x2)=2tan⁡−1x\tan^{-1}\left(\frac{2x}{1-x^2}\right) = 2\tan^{-1}x and tan⁡−1(3x−x31−3x2)=3tan⁡−1x\tan^{-1}\left(\frac{3x-x^3}{1-3x^2}\right) = 3\tan^{-1}x for all x∈Rx \in \mathbb{R}.

Students falling for this will solve 5tan⁡−1x=π45\tan^{-1}x = \frac{\pi}{4} and incorrectly conclude there is only 1 real root.

The rigorous approach requires analyzing the piecewise definitions of these functions across critical points x=±1/3x = \pm 1/\sqrt{3} and x=±1x = \pm 1, revealing two additional valid roots in the outer branches.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterRelations and Functions - Class 12
ConceptInjective Mapping (One-One)
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree