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Question #41178

Difficulty: 8/10 | 🟢 Free

The Question

Let f(x)f(x) be a real-valued function defined implicitly by the equation sin⁡3(f(x))+2sin⁡(f(x))=x4−8x2+12\sin^3(f(x)) + 2\sin(f(x)) = x^4 - 8x^2 + 12 where f(x)∈[−π2,π2]f(x) \in \left[-\frac{\pi}{2}, \frac{\pi}{2}\right]. Let SS be the set of all x∈Rx \in \mathbb{R} at which f(x)f(x) attains either its global maximum or its global minimum. Find the value of ∑x∈Sx2\sum_{x \in S} x^2.

Options

  • A.

    8

  • B.

    16

  • C.

    32

  • D.

    64

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Domain Constraint Intersections|Implicit to Explicit Conversion|Second Derivative Test Limitations

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to handle implicit-to-explicit function conversion alongside strict domain constraints.

The core trap lies in the 'Second Derivative Test' and standard critical point analysis.

Students typically differentiate the polynomial h(x)=x4−8x2+12h(x) = x^4 - 8x^2 + 12 to find extrema at x=0,±2x=0, \pm 2.

However, the inverse trigonometric domain strictly bounds h(x)∈[−3,3]h(x) \in [-3, 3], completely excluding these critical points from the function's domain.

Consequently, the true global extrema occur exclusively at the non-differentiable boundary points of the domain, forcing students to abandon blind differentiation in favor of first-principle boundary analysis.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterInverse Trigonometric Functions - Class 12
ConceptDomain Constraint Intersections
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree