Start Learning Free

Before You Begin

Question #41206

Difficulty: 8/10 | 🟢 Free

The Question

Let A(x)=(0x−1000x(x−1)200)A(x) = \begin{pmatrix} 0 & x-1 & 0 \\ 0 & 0 & x \\ (x-1)^2 & 0 & 0 \end{pmatrix}. A curve C:y=f(x)C: y = f(x) passes through the point (2,1)(2, 1). The slope of the tangent to CC at any point (x,f(x))(x, f(x)) is given by 13tr(A(x)3)\frac{1}{3}\text{tr}(A(x)^3). Let S1S_1 be the set of all xx-coordinates where f(x)f(x) attains a local minimum, and S2S_2 be the set of all xx-coordinates where f(x)f(x) attains a local maximum. Find the value of 20(∑x∈S1f(x)−∑x∈S2f(x))20 \left( \sum_{x \in S_1} f(x) - \sum_{x \in S_2} f(x) \right). (If a set is empty, its sum is taken as 00).

Options

  • A.

    -1

  • B.

    1

  • C.

    -12

  • D.

    11

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Idempotent and Involutory Properties|Tangent/Normal Slope Interplay|Second Derivative Test Limitations

Why This Question Is Tricky

Common Mistakes

This question targets a classic vulnerability in calculus applications: the over-reliance on the Second Derivative Test.

By engineering the derivative f′(x)=x(x−1)3f'(x) = x(x-1)^3, the second derivative vanishes at the local minimum x=1x=1 (f′′(1)=0f''(1)=0).

Students who blindly apply the second derivative test will incorrectly classify x=1x=1 as a point of inflection, leading them to assume S1S_1 is empty and select the trap option -12.

The problem forces the use of the First Derivative Test or higher-order analysis, while simultaneously testing matrix multiplication and trace properties as a rigorous entry barrier.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterMatrices - Class 12
ConceptIdempotent and Involutory Properties
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree