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Question #41223

Difficulty: 8/10 | 🟢 Free

The Question

Let A(x)=(e1/xsin⁡x11x11x1x−x2ln⁡(1+1x)1)A(x) = \begin{pmatrix} e^{1/x} & \sin x & 1 \\ \frac{1}{x} & 1 & \frac{1}{x} \\ 1 & x - x^2 \ln\left(1+\frac{1}{x}\right) & 1 \end{pmatrix} Evaluate lim⁡x→∞(xdet⁡(A(x)))x2\lim_{x \to \infty} \left( x \det(A(x)) \right)^{x^2}

Options

  • A.

    e1/4e^{1/4}

  • B.

    e1/2e^{1/2}

  • C.

    e−1/4e^{-1/4}

  • D.

    11

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Singular vs Non-Singular Matrices|Indeterminate Forms|Infinite Limit Behavior|Denominator Restriction

Why This Question Is Tricky

Common Mistakes

This question tests the evaluation of indeterminate forms arising from the determinant of a variable matrix, specifically targeting the 1∞1^\infty form.

The trap lies in the 'Denominator Restriction' and limit splitting: students often incorrectly assume lim⁡(f(x)g(x))h(x)=lim⁡f(x)h(x)lim⁡g(x)h(x)\lim (f(x)g(x))^{h(x)} = \lim f(x)^{h(x)} \lim g(x)^{h(x)}.

Here, the individual limits lim⁡t→0(et−1t)1/t2\lim_{t \to 0} (\frac{e^t-1}{t})^{1/t^2} and lim⁡t→0(ln⁡(1+t)t)1/t2\lim_{t \to 0} (\frac{\ln(1+t)}{t})^{1/t^2} diverge to ∞\infty and 00 respectively due to the non-zero O(t)O(t) terms in their expansions.

However, their product cancels the O(t)O(t) term, making the combined limit converge to e1/4e^{1/4}.

Blindly applying L'Hôpital's rule or splitting the limit leads to a lethal collision of undefined terms.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterMatrices - Class 12
ConceptSingular vs Non-Singular Matrices
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree