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Question #41225

Difficulty: 8/10 | 🟢 Free

The Question

Let y=f(x)y = f(x) be the particular solution to the exact differential equation (2xyex2)dx+(ex2+2y)dy=0(2x y e^{x^2})dx + (e^{x^2} + 2y)dy = 0 satisfying f(0)=1f(0) = 1. Let the function g(x)g(x) be defined as g(x)=lim⁡n→∞246x2n+1246x2n+1g(x) = \lim_{n \to \infty} \frac{246 x^{2n} + \frac{1}{246}}{x^{2n} + 1} Define the matrix A(x)A(x) as A(x)=(f(x)f(g(x))ex2e(g(x))2)A(x) = \begin{pmatrix} f(x) & f(g(x)) \\ e^{x^2} & e^{(g(x))^2} \end{pmatrix} The product of all real values of xx for which the matrix A(x)A(x) is singular is:

Options

  • A.

    11

  • B.

    −1-1

  • C.

    2462246^2

  • D.

    246−2246^{-2}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Singular vs Non-Singular Matrices|Exact Differential Recognition|Composition Continuity

Why This Question Is Tricky

Common Mistakes

This question tests the synthesis of exact differential equations, functional analysis, and limit-defined piecewise functions.

The 'Lethal Collision' occurs when students assume the composition f(g(x))f(g(x)) inherits the global properties of f(x)f(x) without analyzing the jump discontinuities of g(x)g(x).

The exact DE yields a function f(x)f(x) that makes the matrix determinant equation reduce to ∣x∣=∣g(x)∣|x| = |g(x)|.

Students often fall into the trap of assuming g(x)g(x) is continuous or ignoring the absolute value, missing the negative roots or the roots in the ∣x∣<1|x| < 1 domain.

The '246' constants act as a distractor, but carefully evaluating the piecewise limit reveals exactly four symmetric roots whose product elegantly collapses to 1.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterMatrices - Class 12
ConceptSingular vs Non-Singular Matrices
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree