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Question #41234

Difficulty: 8/10 | 🟢 Free

The Question

Let A=I+KA = I + K be a 4×44 \times 4 matrix, where II is the identity matrix and K=[kij]K = [k_{ij}] is a skew-symmetric matrix with real entries. It is given that k12=1k_{12}=1, k13=2k_{13}=2, k14=3k_{14}=3, k24=2k_{24}=2, k34=1k_{34}=1, and k23=−xk_{23}=-x for some x>0x > 0. If det⁡(K)=36\det(K) = 36, find the value of det⁡(A)\det(A).

Options

  • A.

    37

  • B.

    57

  • C.

    65

  • D.

    17

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Symmetric and Skew-Symmetric Decomposition|Inversion and Determinant Product|Row/Column Exchange Parity

Why This Question Is Tricky

Common Mistakes

This question targets the non-linear properties of determinants and the spectral structure of skew-symmetric matrices.

The primary trap is the false linearity assumption det⁡(I+K)=det⁡(I)+det⁡(K)=37\det(I+K) = \det(I) + \det(K) = 37.

A secondary trap lies in the Pfaffian expansion of a 4×44 \times 4 skew-symmetric matrix: students frequently miss the negative sign in the parity of permutations (k12k34−k13k24+k14k23k_{12}k_{34} - k_{13}k_{24} + k_{14}k_{23}), leading to an incorrect value of xx.

Finally, by recognizing that det⁡(I+K)\det(I+K) is simply the characteristic polynomial P(λ)=det⁡(λI−K)P(\lambda) = \det(\lambda I - K) evaluated at λ=−1\lambda = -1, the student bypasses a brutal and error-prone 4×44 \times 4 determinant expansion, rewarding deep conceptual understanding of matrix invariants.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterMatrices - Class 12
ConceptSymmetric and Skew-Symmetric Decomposition
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree