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Question #41264

Difficulty: 8/10 | 🟢 Free

The Question

Let A(x)=(1sin⁡xx+cos⁡x−sin⁡x1x2+exx−cos⁡xx2−ex4x4−8x3+7x2+5)A(x) = \begin{pmatrix} 1 & \sin x & x + \cos x \\ -\sin x & 1 & x^2 + e^x \\ x - \cos x & x^2 - e^x & 4x^4 - 8x^3 + 7x^2 + 5 \end{pmatrix}.

Define f(x)=det⁡(A(x)+AT(x)2)+det⁡(A(x)−AT(x)2)f(x) = \det\left(\frac{A(x) + A^T(x)}{2}\right) + \det\left(\frac{A(x) - A^T(x)}{2}\right).

If SS is the sum of all local extreme values of the function f(x)f(x), then the value of SS is:

Options

  • A.

    5

  • B.

    11

  • C.

    6

  • D.

    16

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Properties of Transpose Determinant|Symmetric and Skew-Symmetric Decomposition|Second Derivative Test Limitations

Why This Question Is Tricky

Common Mistakes

This question tests the properties of determinants for symmetric and skew-symmetric matrices, combined with a classic calculus trap.

Students must first recognize that the determinant of an odd-order skew-symmetric matrix is zero, simplifying the function to the determinant of the symmetric part.

The primary trap lies in the second derivative test: the critical point at x=1 yields f''(1)=0.

Students who blindly assume all critical points are extrema (or fail to check the sign change of the first derivative) will incorrectly include f(1)=6 in their sum, leading to the trap answer 11.

The true nature of x=1 is a point of inflection.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterDeterminants - Class 12
ConceptProperties of Transpose Determinant
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree