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Question #41265

Difficulty: 8/10 | 🟢 Free

The Question

Let a⃗=(x2−5)i^+xj^+k^\vec{a} = \left(\sqrt{x^2} - 5\right)\hat{i} + x\hat{j} + \hat{k}, b⃗=xi^+(x2−5)j^+k^\vec{b} = x\hat{i} + \left(\sqrt{x^2} - 5\right)\hat{j} + \hat{k}, and c⃗=2i^+j^+k^\vec{c} = 2\hat{i} + \hat{j} + \hat{k}. Let SS be the set of all real values of xx for which the vectors a⃗,b⃗\vec{a}, \vec{b}, and c⃗\vec{c} are coplanar. Find the value of 4∑x∈Sx24 \sum_{x \in S} x^2.

Options

  • A.

    89

  • B.

    64

  • C.

    114

  • D.

    45

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Linear Dependency of Rows|Scalar Triple Product Volume Logic|Unit Vector Normalization|Square Root and Modulus Logic

Why This Question Is Tricky

Common Mistakes

This question tests the evaluation of the scalar triple product for coplanarity while embedding a critical algebraic trap: the simplification of x2\sqrt{x^2}.

Students frequently and incorrectly assume x2=x\sqrt{x^2} = x instead of the rigorous ∣x∣|x|.

If this mistake is made, the determinant equation collapses to a linear equation yielding only the positive root (x=4x=4), causing them to miss the degenerate case for the negative root (x=−5/2x=-5/2) where a⃗\vec{a} and b⃗\vec{b} become identical vectors.

Falling for this trap leads directly to the incorrect option 64.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterDeterminants - Class 12
ConceptLinear Dependency of Rows
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree