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Question #41297

Difficulty: 8/10 | 🟢 Free

The Question

Let A(x)=(1xx21[x][x]21x+[x](x+[x])2)A(x) = \begin{pmatrix} 1 & x & x^2 \\ 1 & [x] & [x]^2 \\ 1 & x+[x] & (x+[x])^2 \end{pmatrix}, where [x][x] denotes the greatest integer less than or equal to xx. Let f(x)=det⁡(adj(A(x)))f(x) = \det(\text{adj}(A(x))). If SS is the set of all points in the interval (−4,5)(-4, 5) where f(x)f(x) is not differentiable, find the value of ∑k∈S(k+2)\sum_{k \in S} (k+2).

Options

  • A.

    15

  • B.

    20

  • C.

    18

  • D.

    17

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Factor Theorem in Determinants|Adjoint-Determinant Relation|Step Function Discontinuities

Why This Question Is Tricky

Common Mistakes

This question tests the application of the Factor Theorem on determinants and the Adjoint-Determinant relation det⁡(adj(A))=∣A∣n−1\det(\text{adj}(A)) = |A|^{n-1}.

The primary trap lies in the differentiability analysis of the resulting step-function dependent expression.

Students often mistakenly assume that the presence of [x][x] and {x}\{x\} implies non-differentiability at all integers.

Furthermore, if a student incorrectly uses ∣A∣|A| instead of ∣A∣2|A|^2 for the adjoint determinant, the function remains non-differentiable at x=0x=0 and x=1x=1, leading to the trap answer 20.

The squaring effect from the adjoint relation smooths out the 'corners' at x=0x=0 and x=1x=1, making the function differentiable specifically at those two integer points.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterDeterminants - Class 12
ConceptFactor Theorem in Determinants
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree