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Question #41300

Difficulty: 8/10 | 🟢 Free

The Question

Evaluate the following limit: lim⁡x→0cos⁡−1(ex2+[x2]−x2)∣x∣\lim_{x \to 0} \frac{\cos^{-1}\left( e^{x^2} + [x^2] - x^2 \right)}{|x|} where [⋅][ \cdot ] denotes the greatest integer function.

Options

  • A.

    0

  • B.

    1

  • C.

    12\frac{1}{2}

  • D.

    \text{Does not exist}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Limit Existence at Discontinuity|Principal Value Branch Boundaries|Step Function Discontinuities

Why This Question Is Tricky

Common Mistakes

This question constructs a 'Lethal Collision' between the domain boundaries of inverse trigonometric functions and the behavior of transcendental functions near zero.

Students often blindly apply Taylor series expansions (e.g., ex2−x2≈1+x4/2e^{x^2} - x^2 \approx 1 + x^4/2) and assume that since the argument approaches 1, the limit evaluates to 0.

The trap lies in ignoring the strict inequality ex2−x2>1e^{x^2} - x^2 > 1 for all x≠0x \neq 0.

Because the argument strictly exceeds the principal value branch domain [−1,1][-1, 1] of cos⁡−1\cos^{-1}, the function is entirely undefined in any punctured neighborhood of zero, making the limit non-existent.

The inclusion of the Greatest Integer Function [x2][x^2] serves as secondary DNA to obfuscate the argument and force piecewise consideration, further distracting from the domain violation.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterContinuity and Differentiability - Class 12
ConceptLimit Existence at Discontinuity
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree