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Question #41331

Difficulty: 8/10 | 🟢 Free

The Question

Let Sn(x)=∑k=1nx(1−k(k−1)x2)(1+(k−1)2x2)(1+k2x2)S_n(x) = \sum_{k=1}^n \frac{x(1 - k(k-1)x^2)}{(1+(k-1)^2 x^2)(1+k^2 x^2)}.

Since Sn(0)=0S_n(0) = 0 and lim⁡x→∞Sn(x)=0\lim_{x \to \infty} S_n(x) = 0, by Rolle's Theorem, Sn(x)S_n(x) has at least one critical point in (0,∞)(0, \infty). Let RnR_n be the unique positive root of Sn′(x)=0S_n'(x) = 0.

Evaluate the limit: lim⁡n→∞n∫0RnSn(x)dx\lim_{n \to \infty} n \int_0^{R_n} S_n(x) dx

Options

  • A.

    ln⁡2\ln 2

  • B.

    ln⁡22\frac{\ln 2}{2}

  • C.

    12\frac{1}{2}

  • D.

    0

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Rolle's Theorem Root Existence|V-N Method (Partial Fractions)|Sum to n terms vs. General Term

Why This Question Is Tricky

Common Mistakes

This question tests the V-N method (telescoping sums) and the application of Rolle's Theorem to a sequence of functions.

The primary trap lies in the temptation to take the limit n→∞n \to \infty of Sn(x)S_n(x) before differentiating.

Since lim⁡n→∞Sn(x)=0\lim_{n \to \infty} S_n(x) = 0 for all xx, students might erroneously conclude the limit function's derivative is 00 everywhere, failing to find RnR_n.

This highlights the danger of assuming uniform convergence and swapping limits with derivatives.

By forcing the evaluation of RnR_n for a finite nn first, the problem filters out students who do not respect the order of operations in sequences of functions.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterContinuity and Differentiability - Class 12
ConceptRolle's Theorem Root Existence
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree