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Question #41389

Difficulty: 8/10 | 🟢 Free

The Question

Let z1,z2,z3z_1, z_2, z_3 be the roots of the equation z3−1=0z^3 - 1 = 0 such that Im(z1)=0\text{Im}(z_1) = 0 and Im(z2)>Im(z3)\text{Im}(z_2) > \text{Im}(z_3). Consider the complex-valued function S(θ)=2z1+z2eiθ+z3ei2θS(\theta) = 2z_1 + z_2 e^{i\theta} + z_3 e^{i2\theta} Using differentials, the approximate value of ∣S(0.02)∣|S(0.02)| is:

Options

  • A.

    1+0.0131 + 0.01\sqrt{3}

  • B.

    1+0.0231 + 0.02\sqrt{3}

  • C.

    1−0.0131 - 0.01\sqrt{3}

  • D.

    1−0.0231 - 0.02\sqrt{3}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Approximation via Differentials|Roots of Unity Properties|Geometrical Interpretation of Modulus

Why This Question Is Tricky

Common Mistakes

This question tests the differential approximation of the modulus of a complex function, specifically targeting the geometric interpretation of the complex derivative.

A common trap is assuming that the differential of the modulus d∣S∣d|S| is equal to the modulus of the differential ∣S′(0)∣dθ|S'(0)|d\theta, which ignores the phase coupling between the terms.

By forcing students to evaluate ddθ∣S(θ)∣=Re(S′(θ)S(θ)‾/∣S(θ)∣)\frac{d}{d\theta}|S(\theta)| = \text{Re}(S'(\theta)\overline{S(\theta)}/|S(\theta)|), it exposes the error of treating complex numbers as scalars.

Students who fall for the trap will incorrectly compute ∣S′(0)∣=3|S'(0)| = \sqrt{3} and choose the distractor 1+0.0231 + 0.02\sqrt{3}.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterApplication of Derivatives - Class 12
ConceptApproximation via Differentials
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree