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Question #41410

Difficulty: 8/10 | 🟢 Free

The Question

Let ckc_k be the coefficient of xkx^k in the expansion of x(1−x)−2x(1-x)^{-2} for ∣x∣<1|x| < 1. Define the function f(t)f(t) for t≠0t \neq 0 as: f(t)=lim⁡n→∞∑k=1nn(2n2−t2ck−1)(n2+t2ck2)(n2+t2ck−12)f(t) = \lim_{n \to \infty} \sum_{k=1}^{n} \frac{n(2n^2 - t^2 c_{k-1})}{(n^2 + t^2 c_k^2)(n^2 + t^2 c_{k-1}^2)} Evaluate the limit: L=lim⁡x→011−cos⁡x∫0xt⋅f(t)dtL = \lim_{x \to 0} \frac{1}{1 - \cos x} \int_{0}^{x} t \cdot f(t) dt

Options

  • A.

    1

  • B.

    2

  • C.

    12\frac{1}{2}

  • D.

    4

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Substitution (Change of Variable), Coefficient of x^r in Expansion, The Telescopic Series Trap, Indeterminate Forms

Why This Question Is Tricky

Common Mistakes

This problem constructs a sophisticated hybrid trap by merging a Riemann sum with a telescopic series, disguised within a single rational term derived from binomial coefficients.

Students often attempt to convert the entire summation directly into a Riemann integral, which leads to a complex integral ∫012(1+t2u2)2du\int_0^1 \frac{2}{(1+t^2 u^2)^2} du that is prone to calculation errors.

Alternatively, if they correctly identify the telescopic nature but miss the Riemann component (the 'Telescopic Series Trap'), they obtain an incomplete f(t)f(t).

Furthermore, the problem forces a post-substitution indeterminate limit evaluation; even if f(t)f(t) is found correctly, the student must recognize that the logarithmic terms in the integral of tf(t)t f(t) perfectly cancel out, leaving an indeterminate form 0/00/0 that requires L'Hôpital's rule or Taylor expansion to resolve.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterIntegrals - Class 12
ConceptSubstitution (Change of Variable)
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree