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Question #41539

Difficulty: 8/10 | 🟢 Free

The Question

Let F(x)=∫0x(∫0ysgn(y−2t)et2dt)dyF(x) = \int_{0}^{x} \left( \int_{0}^{y} \text{sgn}(y - 2t) e^{t^2} dt \right) dy for x>0x > 0. Find the value of F′′(2)F''(2).

Options

  • A.

    e−e4e - e^4

  • B.

    −e4-e^4

  • C.

    e2−e4\frac{e}{2} - e^4

  • D.

    e+e4e + e^4

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Axis of Integration Selection|Newton-Leibniz Formula with variable limits|Second Order Derivative Continuity|Limit Existence at Discontinuity

Why This Question Is Tricky

Common Mistakes

This question tests the application of the Newton-Leibniz formula across a point of discontinuity.

Students often blindly apply the Leibniz rule ddx∫0xg(x,t)dt=g(x,x)+∫0x∂g∂xdt\frac{d}{dx} \int_{0}^{x} g(x,t) dt = g(x,x) + \int_{0}^{x} \frac{\partial g}{\partial x} dt, which assumes g(x,t)g(x,t) is continuous.

Here, sgn(y−2t)\text{sgn}(y-2t) introduces a jump discontinuity at t=y/2t=y/2.

The trap is ignoring this discontinuity, leading to the incorrect derivative −ex2-e^{x^2}.

The rigorous approach requires partitioning the integral at the discontinuity before differentiating, effectively selecting a valid domain for the fundamental theorem of calculus.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterApplication of Integrals - Class 12
ConceptAxis of Integration Selection
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree