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Question #41541

Difficulty: 8/10 | 🟢 Free

The Question

Let CC be a curve defined parametrically by x=t2,y=2tx = t^2, y = 2t for t∈Rt \in \mathbb{R}. Let LL be the polar line of the point P(−1,0)P(-1, 0) with respect to CC. If RR is the finite region bounded by CC and LL, evaluate the integral: I=∬Ry2(x+1)31−x dx dyI = \iint_R \frac{y^2}{(x+1)^3 \sqrt{1-x}} \,dx\,dy

Options

  • A.

    π2\frac{\pi}{\sqrt{2}}

  • B.

    π22\frac{\pi}{2\sqrt{2}}

  • C.

    3π42\frac{3\pi}{4\sqrt{2}}

  • D.

    π42\frac{\pi}{4\sqrt{2}}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Horizontal vs Vertical Strips|Parametric Form Manipulation|Polar and Pole Duality|Denominator Restriction

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to bridge coordinate geometry and multivariable calculus by identifying a region defined through pole-polar duality.

The primary trap is the 'Denominator Restriction' at the boundary x=1x=1, which acts as a singularity.

Students who attempt to integrate using horizontal strips will face an intractable function, forcing a strategic switch to vertical strips.

Furthermore, failing to recognize the improper nature of the integral at the polar line LL often leads to incorrect limit evaluations.

The problem rigorously demands mastery over parametric transformations, order of integration reversal, and advanced trigonometric substitutions to resolve the singularity.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterApplication of Integrals - Class 12
ConceptHorizontal vs Vertical Strips
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree