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Question #41546

Difficulty: 8/10 | 🟢 Free

The Question

Let C1C_1 be the locus of points (x,y)(x,y) for x>0x > 0 such that the matrix equation (x1x2x)(uv)=(yx+2)\begin{pmatrix} x & 1 \\ x^2 & x \end{pmatrix} \begin{pmatrix} u \\ v \end{pmatrix} = \begin{pmatrix} y \\ x+2 \end{pmatrix} has at least one solution for (u,v)(u,v). Let C2C_2 be the locus of points (x,y)(x,y) for x>0x > 0 such that the matrix M=(y22x)M = \begin{pmatrix} y & 2 \\ 2 & x \end{pmatrix} has λ=0\lambda = 0 as an eigenvalue. If RR is the region in the first quadrant bounded by C1C_1, C2C_2, and the line x=1x = 1, find the area of RR.

Options

  • A.

    2ln⁡2−12 \ln 2 - 1

  • B.

    2ln⁡2+12 \ln 2 + 1

  • C.

    4ln⁡2−24 \ln 2 - 2

  • D.

    ln⁡2−12\ln 2 - \frac{1}{2}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Intersection Point Accuracy|Characteristic Equation|Linear Dependency of Rows

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to link the consistency of a singular linear system to the geometric locus of a curve.

The 'Lethal Collision' occurs when students blindly apply Cramer's rule or attempt to invert the coefficient matrix without recognizing that the determinant is zero for all x.

If they ignore the linear dependency of the rows, they fail to extract the consistency condition (xy = x+2), leaving the boundary curve C_1 undefined and making it impossible to establish the integration limits for the area calculation.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterApplication of Integrals - Class 12
ConceptIntersection Point Accuracy
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree