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Question #41559

Difficulty: 8/10 | 🟢 Free

The Question

Let RR be the region enclosed by the parametric curve x(t)=t3−3tx(t) = t^3 - 3t and y(t)=(t2−1)2(t2−3)y(t) = (t^2 - 1)^2 (t^2 - 3), where the parameter tt satisfies the inequality (t2−1)2(t2−3)≤0(t^2 - 1)^2 (t^2 - 3) \le 0. The area of the region RR is

Options

  • A.

    96335\frac{96\sqrt{3}}{35}

  • B.

    1664−2883105\frac{1664 - 288\sqrt{3}}{105}

  • C.

    832105\frac{832}{105}

  • D.

    32335\frac{32\sqrt{3}}{35}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Bounded vs Unbounded Regions|Parametric Curve Area|Even Multiplicity Roots

Why This Question Is Tricky

Common Mistakes

This question tests the evaluation of areas bounded by parametric curves and the interpretation of inequalities with even multiplicity roots.

A common trap is assuming that the even multiplicity roots (t=±1t = \pm 1) divide the region into separate loops that must be integrated with absolute values.

However, these roots merely represent points where the curve is tangent to the x-axis, and the entire interval [−3,3][-\sqrt{3}, \sqrt{3}] traces a single, simple closed curve.

Splitting the integral at t=±1t = \pm 1 and summing absolute values incorrectly calculates overlapping areas, leading to the trap option.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterApplication of Integrals - Class 12
ConceptBounded vs Unbounded Regions
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree