Start Learning Free

Before You Begin

Question #41562

Difficulty: 8/10 | 🟢 Free

The Question

Let MM be a 3×33 \times 3 matrix with real entries such that det⁡(M)=2\det(M) = 2, and let A=adj(M)A = \text{adj}(M). Let OO be the origin (0,0)(0,0). For any real number xx, let P(x)P(x) be the point (x,det⁡(xA))(x, \det(xA)) and QQ be the point (2,det⁡(2A))(2, \det(2A)) in the xyxy-plane. If S(x)S(x) denotes the area of the triangle OP(x)QOP(x)Q, find the value of the integral ∫−12S(x) dx\int_{-1}^{2} S(x) \, dx

Options

  • A.

    23

  • B.

    9

  • C.

    323\frac{32}{3}

  • D.

    232\frac{23}{2}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

The Modulus Trap|Area of Triangle via Determinants|Determinant Scaling Property

Why This Question Is Tricky

Common Mistakes

This question tests the intersection of linear algebra and integral calculus, specifically targeting the 'Determinant Scaling Trap' and the 'Modulus Trap'.

Students frequently make two critical errors: first, they incorrectly scale the determinant by assuming det⁡(xA)=x2det⁡(A)\det(xA) = x^2\det(A) (associating the 2D triangle context with a 2×22 \times 2 matrix) or det⁡(xA)=xdet⁡(A)\det(xA) = x\det(A), forgetting that AA is a 3×33 \times 3 matrix requiring knk^n scaling.

Second, when integrating the area function S(x)S(x), they drop the absolute value bars, failing to recognize that the determinant's sign changes over the interval [−1,2][-1, 2].

Splitting the integral at x=0x=0 is mandatory to respect the geometric definition of area.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterApplication of Integrals - Class 12
ConceptThe Modulus Trap
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree