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Question #41625

Difficulty: 8/10 | 🟢 Free

The Question

Let L′L' be the orthogonal projection of the line L:x−11=y−1=z−22L: \frac{x-1}{1} = \frac{y}{-1} = \frac{z-2}{2} on the plane Π:x+y−z=0\Pi: x + y - z = 0. If the line L′L' intersects the plane 4x−2y+2z=334x - 2y + 2z = 33 at the point P(α,β,γ)P(\alpha, \beta, \gamma), then the value of 2α+2β+γ2\alpha + 2\beta + \gamma is:

Options

  • A.

    15

  • B.

    9

  • C.

    10

  • D.

    12

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Angle between line and plane|Orthogonal projection of a line|Parametric form pitfalls

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to correctly identify the direction ratios of an orthogonally projected line.

A common 'parametric form pitfall' occurs when students incorrectly assume that the orthogonal projection of a line onto a plane merely translates the line, preserving its original direction vector b⃗\vec{b}.

This happens when they treat the parameter tt as a constant during the projection process rather than a varying scalar, leading to a failure in applying the projection operator P=I−n⃗n⃗T∣n⃗∣2P = I - \frac{\vec{n}\vec{n}^T}{|\vec{n}|^2}.

By using the original direction ratios ⟨1,−1,2⟩\langle 1, -1, 2 \rangle instead of the projected ones ⟨5,−1,4⟩\langle 5, -1, 4 \rangle, they arrive at the trap answer 9.

Another trap (yielding 10) catches students who project a single point correctly but still reuse the original direction vector.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterThree-Dimensional Geometry - Class 12
ConceptAngle between line and plane
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree